find the derivative of the function
integral from cosx to sinx (ln(8+3v)dv)
y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2
Is this the right answer?????
2 answers
I gave you my answer which is quite different.
Hmm. I thought that, using Leibniz' Rule,
F'(x) = ln(8+3sinx)*cosx - ln(8+3cosx)(-sinx)
Did I miss something there?
F'(x) = ln(8+3sinx)*cosx - ln(8+3cosx)(-sinx)
Did I miss something there?
1 answer