the derivative of a definite integral is how much the area changes as you change the limits.
d/dx Int from p(x) to q(x) of f(v)dv
= [f(q)-f(p)]dx
(draw a sketch of that graph)
find the derivative of the function
integral from cosx to sinx (ln(8+3v)dv)
4 answers
sorry, extra dx in there
= f(q) - f(p)
f(q) = ln (8+3sin x)
f(p) = ln (8+3cos x)
f(q)-f(p) = ln [ (8+3sin x)/(8+3cos x) ]
= f(q) - f(p)
f(q) = ln (8+3sin x)
f(p) = ln (8+3cos x)
f(q)-f(p) = ln [ (8+3sin x)/(8+3cos x) ]
y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2
Is this the right answer?????
Is this the right answer?????
Well, I gave you my answer which is quite different.