Find the coordinates of point B on Line AC such that AB is 2/3 of AC (B is located in between A and C). A is (1,-5) and C is (-5,4).

Answer 1

C-A is (-6,9)
2/3 of that is (-4,6)

So, B = A + 2/3 (C-A) = (1,-5)+(-4,6) = (-3,1)

Answer 2

A(1, -5), B(x, y), C(-5, 4).

x-1 = 2/3(-5-1).
x-1 = -4,
X = -3.

y-(-5) = 2/3(4-(-5)).
y+5 = 6,
Y = 1.

Answer 3

the coordinates of B are (2, -5)