find cosx and sinx if tanx = 4

2 answers

sin ( x ) = + OR / [ tan (x) /sqrt ( 1 + tan ^2 (x)]

sin ( x ) = + OR - [ 4/ sqrt ( 1 + 4 ^2 ) ]

sin ( x ) = + OR - m4/ sqrt ( 1 + 16 )

sin ( x ) = + OR - 4/ sqrt ( 17)

cos ( x ) = + OR / 1 /sqrt ( 1 + tan ^2 (x)

cos( x ) = + OR - 1 / sqrt ( 17)

If you want all trigonometric identities in google type:

wikipedia List of trigonometric identities
cos ( x ) = + OR - 1 /sqrt ( 1 + tan ^2 (x) )
Similar Questions
  1. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    1. answers icon 5 answers
  2. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
  3. Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
    1. answers icon 1 answer
more similar questions