Ask a New Question
Menu

Prove the following identity:

1/tanx + tanx = 1/sinxcosx

I can't seem to prove it. This is my work, I must've made a mistake somewhere:

Converted 1/tanx: 1/sinx/cosx + sinx/cosx = 1/sinxcosx

Simplified 1/sinx/cosx: cosx/sinx + sinx/cosx = 1/sinxcosx

Found common denominator and multiplied numerator: sinxcosx/sinxcosx + sinxcosx/sinxcosx = 1/sinxcosx

Simplified: 2sinxcosx/sinxcosx

Wouldn't that simplify to just sinxcosx, not 1/sinxcosx?

1 answer

cosx/sinx + sinx/cosx = 1/sinxcosx
common denominator: sinxcosx

(cos^2x+sin^2x)/sinxcosx
not it is proved, as the numberator is 1.
Similar Questions
  1. Prove it is an identity.(sin^2x)/(tanx)=sinxcosx
    1. answers icon 1 answer
  2. How do you verify:1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
    1. answers icon 0 answers
  3. How do I prove that7sin^2x - sinxcosx = 6 can also be written as tan^2x + tanx - 6 = 0 ?
    1. answers icon 2 answers
  4. Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
    1. answers icon 1 answer
more similar questions