cos(3x- ƒÎ/2) = sin(3x)
(Check your trig identities)
3x = sin^-1(-�ã3/2)
= 4 pi/3, 5 pi/3, 10 pi/3, 11 pi/3 etc
x = 4 pi/9 etc
find all the values of X between 0 and 2π such that cos(3x-π/2) = -√3/2
1 answer
1 answer