find all the values of X between 0 and 2π such that cos(3x-π/2) = -√3/2

Answer 1

cos(3x- ƒÎ/2) = sin(3x)
(Check your trig identities)

3x = sin^-1(-�ã3/2)
= 4 pi/3, 5 pi/3, 10 pi/3, 11 pi/3 etc

x = 4 pi/9 etc