Find 3 consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 5 times the third.

Answer 1

6,7,8

Answer 2

let the first be x-1
let the second be x
let the third be x+1

direct translation from English to Math
(math is a language)
(x-1)(x+2 - x = 5(x+1) + 1
x^2 - 1- x = 5x + 5 + 1
x^2 - 6x -7 = 0
(x-7)(x+1)
x = 7 or x = -1, but x is to be positive

so the first is 6
the second is 7
the third is 8