fill the sequence 8, 23, 44,74, 116 next two terms of sequence

12 answers

The magic and wonders of Wolfram:
http://www.wolframalpha.com/input/?i=curve+fit+%281%2C8%29%2C%282%2C23%29%2C%283%2C44%29%2C%284%2C74%29%2C%285%2C116%29

I knew it was a cubic by doing the following

first column are the original values, the second column is the difference between consecutive values, the third column is the difference between those , the fourth column is the difference of the previous column etc

8
23 15
44 21 6
74 30 9 3
116 42 12 3

it looks like the 4th column is a constant, so it must be a cubic
(if the 3rd column is a constant, it must be a quadratic etc)

so the expression producing the above numbers is

term(n) = (n^2 + 23b - 8)/2

What level is this??
Would you know how to solve 4 equations with 4 unknowns ?
forgot to find the next two terms, lol

n=6
term6 = (6^3 + 23(6) - 8)/2 = 173
term7 = (7^3+23(7)-8)/2 = 248

interesting fact:
we can also find the next few terms by simply completing the next row in the above chart
we know the 4th column is a 3
so the number below 12 must be 15, enter it
the number below 42 must be 42+15 or 57
the number below 116 must be 116+57 = 173

etc
thank you. it is grade 7 special math school
That doesn’t make sense!!!
The formula is wrong. It should be term(n) = ( n^3 + 23(n) - 8 ) / 2
What is this?? I don’t think it’s possible...
THAT IS SOOOOOOO CONFUSING
Everything is SOOOOOO CONFUSING!!!
it is confusing
What????
what was the last two numbers tho?
Never mind im dumb.
173 and 248