So am I. If you mean
e^cosx * √(tan(3/4 x)+10)
then I see no problem. tan(3/4 π) = -1
cos π = -1
so the expression at x = π is just
e^-1 √(-1+10) = 3/e
Not sure why a limit is even involved, as there are no 0/0 or ∞ involved anywhere
If I read it wrong, maybe you could format things as I did, and clarify
Evaluate the limit if it exists, otherwise, write ∞,-∞ or DNE as appropriate. (you may not use the L'Hospital Rule)
lim e^cosx \squareroot(tan((3)/(4)x)+10)
x-> π
Please show steps I am very confused!
1 answer
1 answer