Asked by Becky
Find the limit, if it exists. (If an answer does not exist, enter DNE.)
lim (x, y)→(0, 0)
of (x^2 + y^2)/[((x^2 + y^2 +64)^.5)-8]
lim (x, y)→(0, 0)
of (x^2 + y^2)/[((x^2 + y^2 +64)^.5)-8]
Answers
Answered by
Steve
one good way to tackle xy limits is to convert to polar coordinates, then let r->0
f(r,theta) = r^2/(sqrt(r^2+64)-8)
now, using lHospital's Rule,
lim = 2r/[2r/(2sqrt(r^2+64))]
= 2sqrt(r^2+64))
= 2*8 = 16
Since the function does not involve theta, the limit is the same from all directions.
f(r,theta) = r^2/(sqrt(r^2+64)-8)
now, using lHospital's Rule,
lim = 2r/[2r/(2sqrt(r^2+64))]
= 2sqrt(r^2+64))
= 2*8 = 16
Since the function does not involve theta, the limit is the same from all directions.
Answered by
Becky
but there is no lHospitals rule in multivariable
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