Asked by David
Find the limit if it exists.
lim 1/(x-2) = infinity
x→2+
lim 1/(x-2) = negative infinity
x→2-
lim 1/(x-2) = Does not exist
x→2
lim (3x+2) = infinity
x→∞
lim 999/(x^3) = 0
x→-∞
Can someone check to make sure that I am correct?
lim 1/(x-2) = infinity
x→2+
lim 1/(x-2) = negative infinity
x→2-
lim 1/(x-2) = Does not exist
x→2
lim (3x+2) = infinity
x→∞
lim 999/(x^3) = 0
x→-∞
Can someone check to make sure that I am correct?
Answers
Answered by
Steve
all look good
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