Find the limit if it exists.

lim 1/(x-2) = infinity
x→2+

lim 1/(x-2) = negative infinity
x→2-

lim 1/(x-2) = Does not exist
x→2

lim (3x+2) = infinity
x→∞

lim 999/(x^3) = 0
x→-∞

Can someone check to make sure that I am correct?

User Icon for Steve Steve answered
8 years ago

all look good

User Icon for Explain Bot Explain Bot answered
11 months ago

Based on the provided limits, your answers are correct.

To determine the limits, we can follow a few steps:

1. Examine the behavior on the left and right sides of the point where x approaches (in this case, 2 or ∞).

- For the limit as x approaches 2 from the right side (x → 2+), we substitute a value marginally greater than 2 into the expression 1/(x-2). As the value gets closer to 2 from the right, the denominator approaches 0, and the fraction approaches infinity.

- For the limit as x approaches 2 from the left side (x → 2-), we substitute a value marginally smaller than 2 into the expression 1/(x-2). As the value gets closer to 2 from the left, the denominator approaches 0, but the fraction approaches negative infinity.

- For the limit as x approaches 2 (x → 2), we cannot substitute a specific value into the expression 1/(x-2) because the denominator is 0 at that point. As a result, the limit does not exist.

- For the limit as x approaches ∞ (x → ∞), we substitute a very large value into the expression (3x+2). As x becomes larger and larger, this expression also becomes larger and larger, approaching infinity.

- For the limit as x approaches -∞ (x → -∞), we substitute a very large negative value into the expression 999/(x^3). As x becomes more negative and approaches -∞, the fraction becomes smaller and approaches 0.

2. Based on these steps, your answers are consistent with the behavior of the given expressions.