Evaluate 1/3 + square root(3)/12 + 1/16 + square root (3)/64.

Question

I hope this makes sense. Right now we're learning sequences and series and I'm really confused on this question.

Answer 1

1/3 + √3/12 + 1/16 + √3/64
Using a common denominator of 64*3, we have

(64 + 16√3 + 12 + 3√3)/192
(76+19√3)/192
or
19(4+√3)/192