To solve the quadratic equation \((x - 7)^2 = 11\), we start by taking the square root of both sides:
\[ x - 7 = \pm \sqrt{11} \]
This leads to two equations:
- \(x - 7 = \sqrt{11}\)
- \(x - 7 = -\sqrt{11}\)
Now we solve for \(x\) in both cases:
- \(x = 7 + \sqrt{11}\)
- \(x = 7 - \sqrt{11}\)
Now, we can evaluate these two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\).
- The larger solution is \(x = 7 + \sqrt{11}\).
Now, let's approximate \(\sqrt{11}\) for better understanding. The approximation of \(\sqrt{11}\) is about 3.3166.
So, we can find the values:
- \(x = 7 - 3.3166 \approx 3.6834\)
- \(x = 7 + 3.3166 \approx 10.3166\)
Thus, we can fill in the blanks:
- The smaller of the two solutions is \(x \approx 3.6834\).
- The larger of the two solutions is \(x \approx 10.3166\).
Now back to your question:
The smaller of the two solutions is \(x = 7 - \sqrt{11}\). The larger of the two solutions is \(x = 7 + \sqrt{11}\).