During a baseball game, a batter hits a high pop- up. If the ball remains in the air for 6.0s, how high does it rise? Hint: calculate the height using the second half of the trajectory

3 answers

The hint makes it two easy. From what height does it require for something to fall in three seconds.

h=1/2 g t^2
176.4m
maybe this help?

vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
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