Draw this and solve this: side line b= 27.15 and c=29.96 and angle A= 25

Answer 1

To solve the triangle with side lengths b=27.15, c=29.96 and angle A=25 degrees, we can use the Law of Sines.

First, draw a triangle with the given information:

```
c=29.96
/\
/ \
/ \ b=27.15
A /______\ B
c=29.96
```

Now, to find angle B, we can use the Law of Sines:

sinA/a = sinB/b = sinC/c

sin(25)/27.15 = sin(B)/29.96

sin(B) = 29.96 * sin(25) / 27.15
sin(B) ≈ 0.280592399

B = sin^(-1)(0.280592399)
B ≈ 16.05 degrees

To find angle C, we can use the fact that the sum of angles in a triangle is 180 degrees:

C = 180 - A - B
C = 180 - 25 - 16.05
C ≈ 138.95 degrees

Therefore, angle B ≈ 16.05 degrees and angle C ≈ 138.95 degrees.