Given trinagle ABC whose sides are AB=15 in., AC=25 in., and BC=30 in. Form a point D on the side AB, a line DE i drawn to a pointE on side AC such that angle ADE is equal to angle ABC. If the perimeter of triangle ADE is 28 in., find the lengths of line segments BD and CE.

1 answer

since DE and BC are parallel, triangles ABC and ADE are similar.

The ratio of sides of ADE to ABC = 28/70 = 2/5

So,
CE = AC * 3/5 = 15
BD = AB * 3/5 = 9
Similar Questions
  1. draw the following and name them find missing angles...a trinagle has sides 4in,6in and 9in
    1. answers icon 0 answers
  2. Choose the statement that is true.(1 point)Two congruent sides along with a third side larger than the congruent sides will
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Write this statement as a conditional in if-then form:All triangles have three sides. (1 point) Responses If a triangle has
    1. answers icon 9 answers
more similar questions