Unfortunately, I am not able to draw the diagram for you, but I can help you solve the problem based on the information you provided.
To solve for the remaining parts of the triangle, we can use the Law of Sines. The Law of Sines states:
a/sinA = b/sinB = c/sinC
Given angle A = 25 degrees, side b = 27.15, and side c = 29.96, we can use the Law of Sines to solve for the other angles and side lengths.
First, calculate angle B:
27.15/sin(25) = 29.96/sinB
sinB = (29.96 * sin(25))/27.15
sinB ≈ 0.9303
B ≈ sin^(-1)(0.9303)
B ≈ 68.58 degrees
Now, calculate angle C:
180 - 25 - 68.58 = 86.42 degrees
To calculate side length a, use the Law of Sines again:
a/sinA = c/sinC
a/sin(25) = 29.96/sin(86.42)
a ≈ (29.96 * sin(25))/sin(86.42)
a ≈ 13.68
Therefore, the triangle with angle A = 25 degrees, side b = 27.15, and side c = 29.96 has angles: A = 25 degrees, B = 68.58 degrees, C = 86.42 degrees, and side lengths a ≈ 13.68.
Draw this and solve this: angle A =25, side line b=27.15, and c=29.96
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