Label the areas of the triangles with O as a vertex, in the order named above. If we call their areas a,b,c,d then we have
a+b=5
b+c=9
c+d=10
d+a=6
I find no unique solution to that system of equations. I'll have to think on it some more, I guess. Some other geometric property must place an additional constraint on the values.
Diagonals of quadrilateral ABCD intersect at O.If area of triangle ACB is 5 sq.units,area of triangle BCD is 9 sq.units,area of triangle CDA is 10 sq.units and area of triangle DAB is 6 sq.units,Find area of triangle AOB.
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