Rectangle ABCD has diagonals AC and BD. E is the point of intersection of the two diagonals. If the area of triangle AEB is 8, what is the area of triangle ACD?

Question

drwls · Answer

ACD has half the area if the rectangle.

AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.

More information is needed to answer the question.

Reiny · Answer

In a rectangle, the diagonals bisect each other giving you four triangles of equal area. so triangle ACD = 16

drwls · Answer

Whoops! I forgot that equal-area theorem. Thanks again, Reiny.