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Given is a quadrilateral ABCD,diagonals AC and BDare such that AO=BO=CO=DO=3cm,where Ois point of intersection of AC and BD then quadrilateral ABCD is a rectangle State true or false with reason

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True.
Triangle ABO is congruent to triangle CDO.(Side-angle-side equality) Triangle BCO is congruent to triangle DAO (side-angle-side equality)
Opposite pairs of sides of the quadrilateral are equal in length (due to triangle congruency).
Angles A, B, C and D are right angles.(symmetry requirement)
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