Determine if the given equation if BALANCED or UNBALANCED. (5 points)

Question

(5 points)
BALANCED or UNBALANCED
No + 3H, -> 2NH;
2C,H. + 70, -+ 4C02 + 5H,0
C
42nS + 60, -+ 47n0 + 250,
2Fe,03 + 30 - 4Fe + 300,
C}Hs + 50, -> 3002 + 4H20

Answer 1

Let's evaluate each equation one by one to determine if they are BALANCED or UNBALANCED. A chemical equation is balanced if the number of each type of atom is the same on both sides of the equation.

1. Equation: \( \text{No} + 3H_2 \rightarrow 2NH_3 \)

   • Left Side: 1 N, 6 H
   • Right Side: 2 N, 6 H
   • Conclusion: UNBALANCED (the nitrogen atoms are not equal).

2. Equation: \( 2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O \)

   • Left Side: 4 C, 12 H, 14 O
   • Right Side: 4 C, 12 H, 14 O
   • Conclusion: BALANCED.

3. Equation: \( 42nS + 60O_2 \rightarrow 47nO + 250H_2O \)

   • Left Side: 42 S, 120 O
   • Right Side: 47 N, 250 H, 120 O (Note: there’s no nitrogen on the left side, which could indicate a typo. Assuming it meant 47 SO or similar compounds).
   • Conclusion: UNBALANCED (the sulfur and possibly nitrogen are not equal).

4. Equation: \( 2Fe_2O_3 + 3C \rightarrow 4Fe + 3CO_2 \)

   • Left Side: 4 Fe, 6 O, 3 C
   • Right Side: 4 Fe, 6 O, 3 C
   • Conclusion: BALANCED.

5. Equation: \( C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O \)

   • Left Side: 3 C, 8 H, 10 O
   • Right Side: 3 C, 8 H, 10 O
   • Conclusion: BALANCED.

Summary:

1. UNBALANCED
2. BALANCED
3. UNBALANCED
4. BALANCED
5. BALANCED

Please double-check Equation 3 for typing errors regarding the substances involved.