To determine if the given chemical equations are balanced or unbalanced, we need to check if the number of each type of atom on the reactant side (left) is equal to the number on the product side (right). Let's evaluate each equation one by one.
-
N₂ + 3H₂ → 2NH₃
- Reactants: 2 Nitrogen (N) and 6 Hydrogen (H) (1 N₂ + 3 H₂)
- Products: 2 Nitrogen (N) and 6 Hydrogen (H) (2 NH₃)
- Balanced (2 N = 2 N and 6 H = 6 H)
-
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
- Reactants: 4 Carbon (C), 12 Hydrogen (H), and 14 Oxygen (O) (2 C₂H₆ + 7O₂)
- Products: 4 Carbon (C), 12 Hydrogen (H), and 14 Oxygen (O) (4 CO₂ + 6 H₂O)
- Balanced (4 C = 4 C, 12 H = 12 H, 14 O = 14 O)
-
4ZnS + 6O₂ → 4ZnO + 2SO₂
- Reactants: 4 Zinc (Zn), 4 Sulfur (S), and 12 Oxygen (O) (4 ZnS + 6 O₂)
- Products: 4 Zinc (Zn), 2 Sulfur (S), and 8 Oxygen (O) (4 ZnO + 2 SO₂)
- Unbalanced (4 Zn = 4 Zn, 4 S ≠ 2 S, 12 O ≠ 8 O)
-
2Fe₂O₃ + 3C → 4Fe + 3CO₂
- Reactants: 4 Iron (Fe), 6 Oxygen (O), and 3 Carbon (C) (2 Fe₂O₃ + 3 C)
- Products: 4 Iron (Fe), 6 Oxygen (O), and 3 Carbon (C) (4 Fe + 3 CO₂)
- Balanced (4 Fe = 4 Fe, 6 O = 6 O, 3 C = 3 C)
-
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
- Reactants: 3 Carbon (C), 8 Hydrogen (H), and 10 Oxygen (O) (C₃H₈ + 5 O₂)
- Products: 3 Carbon (C), 8 Hydrogen (H), and 10 Oxygen (O) (3 CO₂ + 4 H₂O)
- Balanced (3 C = 3 C, 8 H = 8 H, 10 O = 10 O)
Summary:
- Balanced
- Balanced
- Unbalanced
- Balanced
- Balanced
So, the summary shows that the third equation is unbalanced, while all others are balanced.
1 answer