Derivative of (x^1/2 cscX sinX)

Answer 1

The way you typed it ....
(x^1/2 cscX sinX)
= √x (1/sinx)(sinx)
= x^(1/2)

if y = x^(1/2)
dy/dx = (1/2)x^(-1/2) or 1/(2√x)

Not sure that's what you meant, why is the x in x^(1/2) different
than the x in cscX and sinX ?

Answer 2

just use the product rule
y = √x cscx sinx
actually, since cscx sinx = 1,
y' = 1/2 x^-1/2

Answer 3

ah, Ryan, we seem to be doing a lot of very similar problems for you. It is time to try and post your attempts.