decide whether each equation has one solution, no solution, or infinitely many solutions.

1. 2(x-3) = 2x

2. 3(y-3) = 2y-9+y

3. 10x-2-6x=3x-2+x

4. 4(x+3) = 2x= x-8

please be quick!!

3 answers

simplify each equation, each of which is linear.

If your variable drops out, and
you get a true statement ----> an infinite number of solutions
you get a false statement ---> no solution

If you end up with the variable remaining in the equation, you will have
one solution

e.g. the first one:
2(x-3) = 2x
2x - 6 = 2x
subtract 2x from both sides:
-6 = 0 , which is false, so.... no solution

do the rest in the same way.

btw, you have a typo in the last, two equal signs.

4. 4(x+3) + 2x = x-8

thx mathhelper