Asked by Gwen
Decide whether each equation has one solution, no solution, or infinitely many solutions.
2(x-3)=2x
A. One Solution
B. No solutions
C. Infinitely many solutions
Is the answer A?
2(x-3)=2x
A. One Solution
B. No solutions
C. Infinitely many solutions
Is the answer A?
Answers
Answered by
Mia
Can you show me how you came up with that answer? I like to see a person's though process. It helps me to assist you better.
Answered by
Gwen
Well I did 2*x and 2*3=6
2x-6=2x
2*4-6=2
2*4=8
So wouldn't that be one solution.
If that's not how to solve can you help me figure out how to do it?
2x-6=2x
2*4-6=2
2*4=8
So wouldn't that be one solution.
If that's not how to solve can you help me figure out how to do it?
Answered by
Mia
Okay you first step is first when you multiply it you will get
2x-6=2x
After this you are trying to get x by itself. What would you do?
2x-6=2x
After this you are trying to get x by itself. What would you do?
Answered by
Gwen
Um I don't know how to do that if you could please help me to figure it out.
Answered by
Gwen
2x-6=2x
2-2=0
6-2=4
x=4
Would that be one solution.
2-2=0
6-2=4
x=4
Would that be one solution.
Answered by
Mia
2x-6=2x
Subtract 2x from both sides in order to get your x variables on 1 side
2x-6=2x
-2x -2x
What you do to one side you must also do to the other. This leaves you with
-6=0x
Because it says 0x there is no solution
Subtract 2x from both sides in order to get your x variables on 1 side
2x-6=2x
-2x -2x
What you do to one side you must also do to the other. This leaves you with
-6=0x
Because it says 0x there is no solution
Answered by
unknown
2014? wow... they probably have a family now, ur remembered:)