David is driving at a steady 36.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 1.20 m/s2 at the instant when David passes. How far (in m) does Tina drive before passing David?

Answer 1

d = 36 t

d = (1/2)(1.2) t^2

so
36 t = 0.6 t^2
t = 36/.6

then d = 36 t so d = (36)^2/.6