David is driving a steady 24.0m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.90m/s2 at the instant when David passes.

How far does Tina drive before passing David?

What is her speed as she passes him?

1 answer

t is the time for Tina to catch David

1/2 a t^2 = v t

1.45 t^2 = 24 t

1.45 t^2 - 24 t = 0

t = 24/1.45

distance = 24 * 24/1.45

speed = accel * t = 2.9 * 24/1.45