D is partly constant and partly varies with V. when V=40, D=150 and when V=54, D=192.

Question

(i)find the formula connecting D and V
(ii) find D when V =73.

Answer 1

D = mV + C , ( compare this to your familiar y = mx + b)
when V=40, D=150
150 = 40m + C **
when V=54, D=192
192 = 54m + C ***
subtract ** from ***
42 = 14m
m = 3
sub into ** , 150 = 120 + C
C = 30

so you have D = 3V + 30

sub in your given value of V

Answer 2

D=av+b
solving for a and b
when v=40,D=150 and when v=54,D=192
150=40a+b.........(1)
192=54a+b.........(2)
Subtract (2) from (1)
42=14a
divide both sides by 14
a=3
Substitute a =3 into (1)
150=40×3+b
150=120+b
b=30.
a) find the relationship
D=av+b
D=3v+b
b) find D when v=73
D=3×73+30
D=249

Answer 3

Divine is right

Answer 4

D=av+b
Solution for a and b
When v=40,D=150 and when v=54, D=192
150=40a+b..........(1)
192=54a+b..........(2)

Subtract (1) from (2)
(192=54a+b - 150=40a+b)
42=14a+0
Therefore:- 42=14a
Divide both sides by the co-efficient of (a) which is 14
a=3
Substitute a=3 into (1)
150=40×3+b
150=120+b
Collect like terms
b=150-120
b=30
i. The formula connecting D and V
D=av+b
D=3v+b
ii. D when V=73
D=av+b
D=3v+b
D=(3×73)+30
D=219+30
D=249

Answer 5

Joy is correct

Answer 6

Momoooo ooooo. Fool you no sabi maths. Idiot

Answer 7

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Answer 8

I like it

Answer 9

Correct answer well done ✅

Answer 10

Divine the mumu 🤣 I try it and failed

Answer 11

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Answer 12

I was to solve this early before now but didn't remember the formula of it is bein translated 😍😍😍to the solver's

Answer 13

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I needed the answer.

Answer 14

Thanks i was really in the need of the answer and formula

Answer 15

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Answer 16

Thanks I was I need of the answer and the formula I also got it right in school

Answer 17

x is partly constant and partly various as y, when y=2, x=0 and when y=6, x=20.
Find x when y=3.

Solution.
x=ky + c

0=2k + c ----<1>
20=6k + c ----<2>
Substrate 1 from 2
20 = -4k
Add 4 to both side
20+4 = -4+4k
24=k
Sub.k=24 into <1>
0=2×24+c
0=48+c
C=48
find x when y=3
x = ky + c
x = 24×3+48
x=120//

Answer 18

Good job

Answer 19

Wow great job you really tried because i was really confuse

Answer 20

D=k+mV.
V=40,D=150
150=k+40m
V=54,D=192
192=k+54m(3)-(1):42=14m
m=42/14=3
Substitute for m in (1)
150-k+40(3)
K=150-120=30
So: (i) formulary is D=30+3v
(ii)v=73,d=30+3(73)
=249

Answer 21

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Answer 22

Na your father wa no Sabi math

Answer 23

Maths no be our mate

Answer 24

D is partly constant and partly varies V,when V=40,D=150 and when V=54,D=192
Find the formula connecting D and V
Find D when V=73

Answer 25

D=av+b solving for a and b when V=40,D=150 and when V=54,D=192 150=40 a+b _(1) 192=549+b_(2) subtract (2)from(1)42=149 Divide both sides by 14 9=3substitute 9=3 into (1) 150=40*3+B150=120+B B=30

Answer 26

The formula connecting D and V is: D = 3V + 30

When V = 73:
D = 3(73) + 30
D = 219 + 30
D = 249.

Answer 27

Find the formula connecting D and V

Answer 28

Let D be partly constant and partly vary with V. When V = 40, D = 150 and when V = 54, D = 192.

To find the formula connecting D and V, we can use the two given points to determine the slope (a) and the y-intercept (b) of the equation:

D = aV + b

We can start by finding the slope or the rate of change of D with respect to V:

a = (D₂ - D₁)/(V₂ - V₁)
a = (192 - 150)/(54 - 40)
a = 42/14
a = 3

Next, we can use one of the points to substitute for D, V, and a to solve for b:

150 = 3(40) + b
150 = 120 + b
b = 150 - 120
b = 30

Therefore, the formula connecting D and V is:

D = 3V + 30.