CS2(g) + O2(g) CO2(g) + SO2(g)

(a) Consider the unbalanced equation above. What is the maximum mass of SO2 that can be produced when 46.0 g of CS2 and 29.0 g O2 react?
(b) Assume the reaction in part (a) goes to completion. Calculate the mass of excess reactant.

I figured out part a and got an answer of 38.7 but I'm not sure how to do the 2nd part. Please help!

2 answers

If you did part a correctly, then you know which is the limiting reagent. To do part b, use the limiting reagent and the same kind of stoichiometry you used for part a to determine moles of the other reagent used, then subtract from the initial amount to determine the amount remaining un-reacted. Your answer of 38.7 doesn't help me any. It doesn't have any units (I assume grams) and it doesn't say 38.7 grams of WHAT.
It's 37.9 grams of SO2
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