To determine which elements are unbalanced in the equation \( \text{CH}_4 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{CO}_2 \), we can count the number of atoms of each element on both sides of the equation.
On the reactants side:
- Carbon (C): 1 (from CH4)
- Hydrogen (H): 4 (from CH4)
- Oxygen (O): 2 (from O2)
On the products side:
- Carbon (C): 1 (from CO2)
- Hydrogen (H): 4 (from 2 H2O; 2 H2O contributes 4 H atoms)
- Oxygen (O): 4 (2 from 2 H2O and 2 from CO2)
Now let's compare the counts:
- Carbon: Balanced (1 on each side)
- Hydrogen: Balanced (4 on each side)
- Oxygen: Unbalanced (2 on the reactants side, 4 on the products side)
Therefore, the correct response is:
Only the O is unbalanced.