To solve the quadratic equation \( x^2 + 8x = 9 \) by completing the square, follow these steps:
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Rearrange the equation: Move the constant term to the left side.
\[ x^2 + 8x - 9 = 0 \]
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Isolate the constant term: We want the left side to represent a perfect square.
\[ x^2 + 8x = 9 \]
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Complete the square: Take the coefficient of \( x \) (which is 8), divide it by 2 (giving us 4), and square it (resulting in 16). Now, add and subtract this square inside the equation.
\[ x^2 + 8x + 16 - 16 = 9 \]
This can be rewritten as:
\[ (x + 4)^2 - 16 = 9 \]
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Rearrange it to a standard form:
\[ (x + 4)^2 = 9 + 16 \]
\[ (x + 4)^2 = 25 \]
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Take the square root of both sides: Remember to consider both the positive and negative roots.
\[ x + 4 = 5 \quad \text{or} \quad x + 4 = -5 \]
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Solve for \( x \):
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For \( x + 4 = 5 \):
\[ x = 5 - 4 = 1 \]
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For \( x + 4 = -5 \):
\[ x = -5 - 4 = -9 \]
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So, the two solutions to the equation \( x^2 + 8x = 9 \) are:
\[ \boxed{1} \quad \text{and} \quad \boxed{-9} \]