(CH3)N2H2(l) + 2N204(g) = 3N2(g) + 4H2O(l) + 2CO2(g).

consider the reaction b2n 150g of liquid (CH3)N2H2 & 80L of N2O4 at 27 degree celcius & a pressure of 2 atm. The gases produced are collected at 27 degree celsius in an evacuated 250L. Calculate:

a) Partial pressure of nitrogen produced.

1 answer

You need to do the following:
1. Convert 80L N2O4 at the conditions listed to moles. Use PV = nRT and solve for n.
2. Use stoichiometry to determine the moles N2 produced. Here is an example problem, worked, that shows how to do stoichiometry.
http://www.jiskha.com/science/chemistry/stoichiometry.html
3. Use PV = nRT to convert moles N2O4 at whatever conditions you wish (which the problem doesn't make clear) and solve for P.
By the way, note the correct spelling of celsius.
Similar Questions
    1. answers icon 4 answers
  1. 2CH3OH+3O2---> 2CO2+ 4H2OA. Decomposition reaction B. Double Replacement reaction C. combustion reaction D. Combination or
    1. answers icon 1 answer
    1. answers icon 5 answers
  2. For the reaction2CO2(g) + 5H2(g)C2H2(g) + 4H2O(g) H° = 46.5 kJ and S° = -124.8 J/K The standard free energy change for the
    1. answers icon 1 answer
more similar questions