how many moles of CO did you use?
You could get 3 times that many moles of CH3OH
convert that back to grams.
the yield is just
(what you got) / (what was possible) * 100%
Carbon monoxide gas and hydrogen gas react to form methanol vapour:
CO(g)+2H_2(g)->CH_3OH(g)
1.50*10^4 tonnes of carbon monoxide and the stoichiometric amount of hydrogen are reacted to form methanol at 250 deg. celsius and 10 MPa
a) Calculate the theoretical yield of methanol.
b) Calculate the percentage yield by weight of methanol if 1.67 * 10^4 tonnes of methanol are formed in this reaction.
1 answer