To analyze the given reaction, we start from the balanced chemical equation for the synthesis of methanol (CH₃OH) from carbon monoxide (CO) and hydrogen (H₂). The equation can be represented as:
\[ 2 , \text{CO} + 4 , \text{H}_2 \rightarrow 2 , \text{CH}_3\text{OH} \]
Based on the information provided:
- 4 molecules of CO react with 8 molecules of H₂ to produce methanol.
Number of atoms in the reaction:
-
Hydrogen (H):
- Each H₂ molecule contains 2 hydrogen atoms.
- 4 H₂ molecules have \( 4 \times 2 = 8 \) hydrogen atoms.
-
Carbon (C):
- Each CO molecule contains 1 carbon atom.
- 4 CO molecules have \( 4 \times 1 = 4 \) carbon atoms.
-
Oxygen (O):
- Each CO molecule contains 1 oxygen atom. In this case, we will focus on methanol, which contains 1 oxygen atom as well.
- Yes, if we follow the format of producing methanol, there are still 2 oxygen atoms involved in forming 2 CH₃OH from 2 CO.
Summary Table:
| Chemical element | Number of atoms in the reaction | |------------------|---------------------------------| | H | 8 | | C | 4 | | O | 2 |
Molecules of Methanol Produced:
From the balanced equation, for every 2 molecules of CO and 4 molecules of H₂, we produce 2 molecules of methanol (CH₃OH).
In this case, since we start with 4 molecules of CO, we will produce:
\[ \text{2 CH}_3\text{OH} \text{ per } 2 \text{ CO} \Rightarrow \text{4 CO gives } 4 \text{ CH}_3\text{OH} \]
Thus, 2 molecules of methanol (CH₃OH) are produced from the reaction of 4 CO and 8 H₂.
Therefore, the answer is 2 molecules of methanol (CH₃OH).