add the 3rd equation to the 1st and then the 2nd to eliminate x
1 & 3 ... 5y + 6z = 5 ... (A)
2 & 3 ... 2y + 4z = 2 ... (B)
... multiply by 3/2 ... 3y + 6z = 3 ... (C)
subtract (C) from (A) to eliminate z
... 2y = 2
substitute the y-value back to find x and z
Can someone show me how to solve the system by elimination with?
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
5 answers
So it would go like
-2x+2y+3z=0
2x+3y+3z=5
Equal
0x+5y+6z=5?
-2x-y+z=-3
2x+3y+3z=5
Equal
0x+3y+3z=5
But if I multiply 3/2 with what you got (aka) 2 & 3 ... 2y + 4z = 2 ... (B)
3/2*2=3
3/2*4=6
3/2*2=3
So I’d plug in the variables and get
3y+6z=3
And then subtract
5y + 6z = 5
From
3y + 6z = 3
And get
2y+0z=2
So basically if our variable has 0 it drops (aka) it’s dead? As in we don’t use it?
So I’d get 2y=2... but you said substitute y back to get x and z but how do I do that????
(So basically I have 2 problems with how I just solved this problem #1 I have no clue how you got “B” because I guess I solved it wrong??? And I have no clue on how to substitute y back to find x and z).... I know all I did is somewhat retyped what you said do, but I was showing you why i needed help instead of just being given the answers I needed someone to help explain and guide me step by step so I’d be able to look back and try doing it on my own.
-2x+2y+3z=0
2x+3y+3z=5
Equal
0x+5y+6z=5?
-2x-y+z=-3
2x+3y+3z=5
Equal
0x+3y+3z=5
But if I multiply 3/2 with what you got (aka) 2 & 3 ... 2y + 4z = 2 ... (B)
3/2*2=3
3/2*4=6
3/2*2=3
So I’d plug in the variables and get
3y+6z=3
And then subtract
5y + 6z = 5
From
3y + 6z = 3
And get
2y+0z=2
So basically if our variable has 0 it drops (aka) it’s dead? As in we don’t use it?
So I’d get 2y=2... but you said substitute y back to get x and z but how do I do that????
(So basically I have 2 problems with how I just solved this problem #1 I have no clue how you got “B” because I guess I solved it wrong??? And I have no clue on how to substitute y back to find x and z).... I know all I did is somewhat retyped what you said do, but I was showing you why i needed help instead of just being given the answers I needed someone to help explain and guide me step by step so I’d be able to look back and try doing it on my own.
you have found y=1
You also have
5y+6z=5
so, 5+6z = 5, so z=0
Now you have any of the original equations, such as
2x+3y+3z=5
2x+3+0=5
x=1
You also have
5y+6z=5
so, 5+6z = 5, so z=0
Now you have any of the original equations, such as
2x+3y+3z=5
2x+3+0=5
x=1
So does that mean for “B” I was right? Or did you just go with mine?...and I’m still confused on how you found x, for everything else I understand now. Thank you
So it would go like
-2x+2y+3z=0
2x+3y+3z=5
Equal
0x+5y+6z=5?
-2x-y+z=-3
2x+3y+3z=5
Equal
0x+3y+3z=5
But if I multiply 3/2 with what you got (aka) 2 & 3 ... 2y + 4z = 2 ... (B)
3/2*2=3
3/2*4=6
3/2*2=3
So I’d plug in the variables and get
3y+6z=3
And then subtract
5y + 6z = 5
From
3y + 6z = 3
And get
2y+0z=2
So basically if our variable has 0 it drops (aka) it’s dead? As in we don’t use it?
So I’d get 2y=2... but you said substitute y back to get x and z but how do I do that????
(So basically I have 2 problems with how I just solved this problem #1 I have no clue how you got “B” because I guess I solved it wrong??? And I have no clue on how to substitute y back to find x and z).... I know all I did is somewhat retyped what you said do, but I was showing you why i needed help instead of just being given the answers I needed someone to help explain and guide me step by step so I’d be able to look back and try doing it on my own.
-2x+2y+3z=0
2x+3y+3z=5
Equal
0x+5y+6z=5?
-2x-y+z=-3
2x+3y+3z=5
Equal
0x+3y+3z=5
But if I multiply 3/2 with what you got (aka) 2 & 3 ... 2y + 4z = 2 ... (B)
3/2*2=3
3/2*4=6
3/2*2=3
So I’d plug in the variables and get
3y+6z=3
And then subtract
5y + 6z = 5
From
3y + 6z = 3
And get
2y+0z=2
So basically if our variable has 0 it drops (aka) it’s dead? As in we don’t use it?
So I’d get 2y=2... but you said substitute y back to get x and z but how do I do that????
(So basically I have 2 problems with how I just solved this problem #1 I have no clue how you got “B” because I guess I solved it wrong??? And I have no clue on how to substitute y back to find x and z).... I know all I did is somewhat retyped what you said do, but I was showing you why i needed help instead of just being given the answers I needed someone to help explain and guide me step by step so I’d be able to look back and try doing it on my own.