Asked by anonymous

can someone show me how to solve an equation algerbracially

x=sqrtx+10+2

Answers

Answered by bobpursley
x-sqrtx-12=0

let sqrtx=u
u^2-u-12=0
(u-4)(u+3)=0

u=4 or sqrt x=4 or x=16
u=-3 or sqrtx=-4 or x=16
Answered by Anonymous
sorry the equation should read x=sqrt(x+10)+2
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