Can someone pleas help I have this assignment and the only question I cannot figure out is to describe the hybridization of all the covalent bonds in oxalic acid? and label those bonds as sigma or pi bonds?
I have determine that oxilic acid formula is HO_2CCO_2H and its compound formula is C_2H_2O_4
2 answers
disregard, I found the answer
The structure of oxalic acid is shown at:
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Each carbon atom is connected to 3 other atoms (1 double and 2 single bonds). That is sp^2 hybridization.
The two double bonded oxygen atoms are also sp^2 hybridized (1 double bond and 2 nonbonding electron pairs on each)
The two oxygen atoms that are bonded to hydrogens are sp^3 hybridized (2 bonding and two nonbonding pairs each)
The 2 hydrogen atoms are not hybridized.
NOTE: You need to copy the above structure and fill in the nonbonding electron pairs to see the Lewis structure on which hybridization is based.
(Broken Link Removed)
Each carbon atom is connected to 3 other atoms (1 double and 2 single bonds). That is sp^2 hybridization.
The two double bonded oxygen atoms are also sp^2 hybridized (1 double bond and 2 nonbonding electron pairs on each)
The two oxygen atoms that are bonded to hydrogens are sp^3 hybridized (2 bonding and two nonbonding pairs each)
The 2 hydrogen atoms are not hybridized.
NOTE: You need to copy the above structure and fill in the nonbonding electron pairs to see the Lewis structure on which hybridization is based.