Can someone help me with this question. With steps.

Examine the continuity of the function

h(x)=

-x, if x<0
0, if x=0
x, if x>0

3 answers

What would be discontinous at x=?

explain please
This is just h(x) = |x|
h is continuous at x=0, but

h' is discontinuous at x=0, since
h'(x) = -1 for x < 0
h'(x) = 1 for x > 0
Is there suppose to be calculations involved? :|
Similar Questions
  1. Is this the right explanation for this question1. Examine the continuity of the function h(x)= -x, if x<0 0, if x=0 x, if x>0
    1. answers icon 1 answer
  2. Examine the continuity of the functionh(x)=[-x, if x<0 .......0, if x=0 .......x, if x>0 I don't understand this question...
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Can you please help me get some datas, to help me answer this question.What is the difference between absolute continuity and
    1. answers icon 4 answers
more similar questions