calculate the volume of 0.0321M NaOH that will be required to neutralize 25.00 mL of a 0.0399M hydrochloric acid solution.

M1v1=m2v2

since were trying to find out the volume I would change the equation to m2 times V2 divided by M1

0.0399 X 0.025/0.0321 =0.031L

I don't know if this is right

1 answer

It looks ok to me.

Ask a New Question or answer this question.

Similar Questions

In a given experiment 36.44 mL of NaOH were required for neutralize a solution of HCl 0.35 M.Calculate the moles of NaOH present
1. 1 answer
Calculate the amount (volume) of 0.135 M HClO4 solution required to neutralize 57.00 mL of .089 M NaOH
1. 1 answer
The volume of a sample of pure HCl gas was 161 mL at 26°C and 139 mmHg. It was completely dissolved in about 60 mL of water and
1. 1 answer
What volume of 0.500 M hydrochloric acid is required to exactly neutralize 40.00 mL 0.150 M NaOH?
1. 2 answers