This is a 1:1 acid/base reaction.
HClO4 + NaOH ==> NaClO4 + H2O
mL1 x M1 = mL2 x M2
Substitute and solve for the unknown.
Calculate the amount (volume) of 0.135 M HClO4 solution required to neutralize 57.00 mL of .089 M NaOH
1 answer
2 answers