A)What volume of 0.145 M HClO4 solution is needed to neutralize 46.00 mL of 8.75×10−2 M NaOH?

B)What volume of 0.138 M HCl is needed to neutralize 2.79 g of Mg(OH)2?

1 answer

HClO4 + NaOH = NaClO4 + H2O
How many moles of NaOH do you have?
0.046L * 8.75*10^-2 moles/L = 0.004025 moles
So, you will need that many moles of HClO4
0.004025 mol * 1000mL/0.145mol = 27.758 mL of HClO4

do the other the same way