mols primary std = g/molar mass = 0.4125/HgO = approximately 0.002 but you need to do that more accurately.
Convert mols HgO to mols OH^- = approx 0.004 (again redo all of this).
HClO4 + OH^- ==> H2O + ClO4^-
0.004 mols OH will consume 0.004 mol HClO4
M HClO4 = mols HClO4/L HClO4. = approx 0.004/0.04651 = ? (approx)
A solution of HClO4 was standardized by dissolving 0.4125 g of primary standard grade HgO ina solution of KBR: HgO (s) + 4Br- + H2O → HgBr4 + 2OH-
The liberated OH- consumed 46.51 mL of the acid. calculate the molarity of the HClO4
3 answers
0.08190M
139
2 answers