Part 1 of 2:
[H3O+] = 5.00 x 10^-7 M
pH = -log(5.00 x 10^-7) = 6.30
Part 2 of 2:
[H3O+] = 0.0024 M
pH = -log(0.0024) = 2.62
Calculate the pH from each H3OT concentration.
Part 1 of 2
[H30 *= 5.00 x 10-7
pH =
M. Be sure your answer has the correct number of significant figures.
10
X
Part 2 of 2
[H3 0* = 0.0024 M. Be sure your answer has the correct number of significant figures.
pH =
10
X
the answer for number 1 is not 6.30 make the significant figure longer
1 answer