Part 1: pH = -log(5.10 x 10^-8) = 7.29
Part 2: pH = -log(0.0014) = 2.85
Calculate the pH from each H3OT concentration.
Part 1 of 2
[H30+= 5.10 x 10"8 M. Be sure your answer has the correct number of significant figures.
pH =
10
X
Part 2 of 2
H30+ = 0.0014 M. Be sure your answer has the correct number of significant figures.
pH =
10
x
1 answer