Part 1 of 2:
Since [H3O+] = 10^-10 M, we can use the ion product of water to calculate the value of [OH-].
[H3O+][OH-] = 1.0 x 10^-14
10^-10 [OH-] = 1.0 x 10^-14
[OH-] = 1.0 x 10^-4 M
This solution is basic.
Part 2 of 2:
Since [H3O+] = 5.4 x 10^-7 M, we can use the ion product of water to calculate the value of [OH-].
[H3O+][OH-] = 1.0 x 10^-14
5.4 x 10^-7 [OH-] = 1.0 x 10^-14
[OH-] = 1.85 x 10^-8 M
This solution is basic.
Calculate the value of [OH] from the given | H3OT | in each solution and label the solution as acidic, basic, or neutral.
Note: The ion product of water = 1.0 x 1014
Part 1 of 2
M
×
Be sure your answer has the correct number of significant figures.
[H30+]=10-10 M
[OH7]=
This solution is
(Choose one)
Part 2 of 2
Be sure your answer has the correct number of significant figures.
[H30+=5.4x1079 M
[OH-]=
This solution is
10
M
(Choose one)
1 answer