calculate the number of grams of alcohol present in 1.70 L OF 75-Proof gin. The density of ethanol is 0.798 g/ml. Proof--> twice the % by volume of ethanol(C2H5OH) present.

Answer 1

75 proof = 37.5% v/v
That means 37.5 mL ethanol/100 mL sample. You have 1700 mL; therefore, you have
37.5 x (1700/100) = ?? mL ethanol.
Use the density to convert to grams.