The mass of sulphuric (vi) acid in 250 cm of a solution whose concentration is 0.25 mole dm-3 is 62.5 g.
To calculate this, we need to use the formula:
Mass = Concentration x Volume
Mass = 0.25 mole dm-3 x 250 cm3
Mass = 62.5 g
Calculate the mass of sulphuric (vi) acid in 250cm of a solution whose concentration is 0.25 mole dm-3
1 answer