5,10g of pure silver nitrate is dessolved in 250cm of water .calculate the concentration of solution.(0,120mol.dm)

Answer 1

To calculate the concentration of the solution, we need to convert the mass of silver nitrate to moles using its molar mass. The molar mass of AgNO3 is 169.87 g/mol.

Number of moles of AgNO3 = mass of AgNO3 / molar mass of AgNO3

Number of moles of AgNO3 = 5.10 g / 169.87 g/mol = 0.0300 mol

Now, we need to calculate the volume of the solution in dm^3. We convert 250 cm^3 to dm^3 by dividing by 1000.

Volume of solution = 250 cm^3 / 1000 = 0.250 dm^3

Finally, we can calculate the concentration of the solution by dividing the number of moles of AgNO3 by the volume of the solution.

Concentration of solution = Number of moles of AgNO3 / Volume of solution
Concentration of solution = 0.0300 mol / 0.250 dm^3 = 0.120 mol/dm3

Therefore, the concentration of the solution is 0.120 mol/dm3.