Calculate the mass of sulphur ric(six)acid in 250 cm3 of a solution whose concentration is 0.25 mole dm-3

Answer 1

To calculate the mass of sulfuric acid (H2SO4) in 250 cm3 of a solution with a concentration of 0.25 mole dm-3, we need to use the equation:

n = c x V

Where:
n = moles of solute
c = concentration in moles per dm3 (mol dm-3)
V = volume of solution in dm3

First, we need to convert the volume from cm3 to dm3:

250 cm3 ÷ 1000 = 0.25 dm3

Now we can calculate the moles of sulfuric acid:

n = 0.25 mol dm-3 x 0.25 dm3
n = 0.0625 moles

The relative molecular mass (Molar Mass) of sulfuric acid (H2SO4) is:
H = 1 g/mol
S = 32 g/mol
O = 16 g/mol (2x Oxygen atoms)

So the molar mass of H2SO4 is:
(2x1) + 32 + (4x16) = 98 g/mol

To find the mass, we multiply the moles by the molar mass:

Mass = Moles x Molar Mass
Mass = 0.0625 moles x 98 g/mol
Mass = 6.125 g

Therefore, the mass of sulfuric acid in 250 cm3 of a solution with a concentration of 0.25 mole dm-3 is 6.125 grams.