To calculate the mass of KH2PO4 needed to prepare 550 mL of a 0.05 M solution, we can use the formula:
mass = molarity × volume × molar mass
First, let's calculate the moles of KH2PO4 needed:
moles = molarity × volume
= 0.05 mol/L × 0.55 L
= 0.0275 mol
Now, let's calculate the mass:
mass = moles × molar mass
= 0.0275 mol × 136.09 g/mol
= 3.716 g
Therefore, you will need 3.716 grams of KH2PO4 to prepare a 550 mL 0.05 M solution.
Calculate the mass of KH2PO4 (136.09 g/mole) you will need to prepare 550 mL of the 0.05 M solution.
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